Алгебра 9 класс учебник Макарычев, Миндюк ответы – номер 593

a) b₁ = 2
q = –6 : 2 = –3
b₇ = b₁q⁶ = 2 · (–3)⁶ = 2 · 729 = 1458
b_n = b₁q^{n - 1}
b_n = 2 · (–3)^{n - 1}

б) b₁ = –40
q = –20 : (–40) = 0,5
b₇ = b₁q⁶ = –40 · 0,5⁶ = –40 · 1/64 = –5/8
b_n = b₁q^{n - 1}
b_n = –40 · 0,5^{n - 1}

в) b₁ = –0,125
q = 0,25 : (–0,125) = –2
b₇ = b₁q⁶ = –0,125 · (–2)⁶ = – 1/8 · 64 = –8
b_n = b₁q^{n - 1}
b_n = –0,125 · (–2)^{n - 1}

г) b₁ = –10
q = 10 : (–10) = –1
b₇ = b₁q⁶ = –10 · (–1)⁶ = –10 · 1 = –10
b_n = b₁^{n - 1}
b_n = –10 · (–1)^{n - 1}