Алгебра 8 класс учебник Макарычев, Миндюк ответы – номер 984

а) $$ \left\{\begin{array} { l } { 5 ( x - 2 ) - x > 2 } \\ { 1 - 3 ( x - 1 ) < - 2 } \end{array} \left\{\begin{array} { l } { 5 x - 1 0 - x > 2 } \\ { 1 - 3 x + 3 < - 2 } \end{array} \left\{\begin{array}{l} 4 x>2+10 \\ -3 x<-2-4 \end{array}\right.\right.\right. $$ $$ \left\{\begin{array} { l } { 4 x > 1 2 } \\ { - 3 x < - 6 } \end{array} \left\{\begin{array} { l } { x > 1 2 : 4 } \\ { x > - 6 : ( - 3 ) } \end{array} \left\{\begin{array}{l} x>3 \\ x>2 \end{array}\right.\right.\right. $$

    (3; +∞)
б) $$ \left\{\begin{array} { l } { 2 y - ( y - 4 ) < 6 } \\ { y > 3 ( 2 y - 1 ) + 1 8 } \end{array} \left\{\begin{array}{l} 2 y-y+4<6 \\ y>6 y-3+18 \end{array}\right.\right. $$ $$ \left\{\begin{array} { l } { y < 6 - 4 } \\ { y - 6 y > 1 5 } \end{array} \left\{\begin{array}{l} y<2 \\ y<15 \end{array}:(-5)\left\{\begin{array}{l} y<2 \\ y<-3 \end{array}\right.\right.\right. $$

    (−∞; −3)
в) $$ \left\{\begin{array} { l } { 7 x + 3 \geq 5 ( x - 4 ) + 1 } \\ { 4 x + 1 \leq 4 3 - 3 ( 7 + x ) } \end{array} \left\{\begin{array}{l} 7 x+3 \geq 5 x-20+1 \\ 4 x+1 \leq 43-21-3 x \end{array}\right.\right. $$ $$ \left\{\begin{array} { l } { 7 x - 5 x \geq - 1 9 - 3 } \\ { 4 x + 3 x \leq 2 2 - 1 } \end{array} \left\{\begin{array} { l } { 2 x \geq - 2 2 } \\ { 7 x \leq 2 1 } \end{array} \left\{\begin{array} { l } { x \geq - 2 2 : 2 } \\ { x \leq 2 1 : 7 } \end{array} \left\{\begin{array}{l} x \geq-11 \\ x \leq 3 \end{array}\right.\right.\right.\right. $$

    [−11; 3]
г) $$ \left\{\begin{array}{l} 3(2-3 p)-2(3-2 p)>p\left\{\begin{array}{l} 6-9 p-6+4 p-p>0 \\ 6< p^2-p(p-8) \end{array}\right. \\ 6-p^2+p^2-8 p < 0 \end{array}\right. $$ $$ \left\{\begin{array} { l } { - 6 p > 0 } \\ { - 8 p < - 6 } \end{array} \left\{\begin{array} { l } { p < 0 : ( - 6 ) } \\ { p > - 6 : ( - 8 ) } \end{array} \left\{\begin{array}{l} p<0 \\ p>\frac{3}{4} \end{array}\right.\right.\right. $$

    Нет решения